Question:
The perpendicular distance from the point (3,-4) to the line 3(x^2)-4(x)+10=0
Answer:
Given equation is
3x2 - 4x + 10 = 0
and the point is (3, -4)
Now distance d = {3*3 - 4*(-4) + 10}/√{9 + 16}
=> d = {9 + 16 + 10}/√25
=> d = 35/5
=> d = 7
So the perpendicular distance is 7 unit.
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